20x^2+16x-384=0

Solution for 20x^2+16x-384=0 equation:

20x^2+16x-384=0

a = 20; b = 16; c = -384;
Δ = b2-4ac
Δ = 162-4·20·(-384)
Δ = 30976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{30976}=176$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-176}{2*20}=\frac{-192}{40}
=-4+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+176}{2*20}=\frac{160}{40}
=4
$